Two gears that are directly touching are called?
1 answer:
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Answer:
the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Explanation:
Given that:
Initial Temperature = 15°C
Initial Pressure = 5 atm
Final Pressure = 1 atm
Data obtain from steam tables of saturated water at 15°C are as follows:
Specific volume v = 1.001 cm³/gm
The change in temperature = 2°C
Specific heat of water = 4.19 J/gm.K
volume expansivity β = 1.5 × 10⁻⁴ K⁻¹
The expression to determine the change in temperature can be given as :
Δ T = 0.093 K
Now; we can calculate the lost work bt the formula:
where ;
is the temperature of the surrounding. = 20°C = (20+273.15)K = 293.15 K
From above the change in entropy is:
Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Answer:
Explanation:
a) the steady-state, 1-D incompressible and no energy generation equation can be expressed as follows:
b) For a transient, 1-D, constant with energy generation
suppose T = f(x)
Then; the equation can be expressed as:
where;
= heat generated per unit volume
= Thermal diffusivity
c) The heat equation for a cylinder steady-state with 2-D constant and no compressible energy generation is:
where;
The radial directional term = and the axial directional term is
d) The heat equation for a wire going through a furnace is:
since;
the steady-state is zero, Then:
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e) The heat equation for a sphere that is transient, 1-D, and incompressible with energy generation is: