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WINSTONCH [101]
2 years ago
7

The National Park Service is waiting on your recommendation.

Engineering
1 answer:
maksim [4K]2 years ago
8 0

The hypothesis that would help restore equilibrium is reintroduce wolves in the park or into the forest.

<h3>What is  reintroduce?</h3>

To reintroduce, is a term that means to revive, reinstate, or bring back something.

Note that based on the right recommendation needed by National Park Service, one can say that the best hypothesis that would help restore equilibrium is reintroduce wolves in the park or into the forest  as it will help restore balance.

Learn more about hypothesis from

brainly.com/question/24149728

#SPJ1

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The real power delivered by a source to two impedances, ????1=4+????5⁡Ω and ????2=10⁡Ω connected in parallel, is 1000 W. Determi
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Answer:

The question is incomplete, below is the complete question

"The real power delivered by a source to two impedance, Z1=4+j5⁡Ω and Z2=10⁡Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."

answer:

a. 615W, 384.4W

b. 17.4A

Explanation:

To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.

recall that the symbol for admittance is Y and express as

Y=\frac{1}{Z}

Hence for each we have,  

Y_{1} =1/Zx_{1}\\Y_{1} =\frac{1}{4+j5}\\converting to polar \\  Y_{1} =\frac{1}{6.4\leq 51.3}\\  Y_{1} =(0.16 \leq -51.3)S

for the second impedance we have

Y_{2}=\frac{1}{10}\\Y_{2}=0.1S

we also determine the voltage cross the impedance,

P=V^2(Y1 +Y2)

V=\sqrt{\frac{P}{Y_{1}+Y_{2}}}\\

V=\sqrt{\frac{1000}{0.16+0.1}}\\ V=62v

The real power in the impedance is calculated as

P_{1}=v^{2}G_{1}\\P_{1}=62*62*0.16\\ P_{1}=615W

for the second impedance

P_{2}=v^{2}*G_{2}\\   P_{2}=62*62*0.1\\384.4w

b. We determine the equivalent admittance

Y_{total}=Y_{1}+Y_{2}\\Y_{total}=(0.16\leq -51.3 )+0.1\\Y_{total}=(0.16-j1.0)+0.1\\Y_{total}=0.26-J1.0\\

We convert the equivalent admittance back into the polar form

Y_{total}=0.28\leq -19.65\\

the source current flows is

I_{s}=VY_{total}\\I_{s}=62*0.28\\I_{s}=17.4A

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An incandescent light bulb can be regarded as a resistor. If its power output is 100W, calculate the resistance of the light bul
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Given

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Resistance of the bulb is given by

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Current drawn by the Power source is given by

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