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OLEGan [10]
3 years ago
15

What's the equation of the parabola that has its vertex at (8,–14) and a point (5,13) that lies on the curve?

Mathematics
1 answer:
finlep [7]3 years ago
6 0

Answer:

The expression with the described characteristics is: y = 3*(x - 8)^2 - 14. Therefore the correct answer is letter D.

Step-by-step explanation:

I believe there is a typo in the vertex's coordinate, I think it should be (8,14). I came to this conclusion by observing the possible answers, if the given vertex is correct then there are no correct answers among them. I made my best effort to explain the question in a way that can be generalized for different vertex's coordinates.

The equations are given in their vertex form. This form has the following structure:

y = a*(x - h)^2 - k

Where (h,k) are the vertex's coordinates, in our case (8, 14). This knowledge makes easier to determine a equation with the correct vertex as shown below:

y = a*(x - 8)^2 - 14

Where the value of "a" must be determined by applying the given point.

13 = a*(5 - 8)^2 - 14\\13 = a*(3)^2 - 14\\a*9 = 27\\a = \frac{27}{9}\\a = 3

The expression with the described characteristics is: y = 3*(x - 8)^2 - 14. Therefore the correct answer is letter D.

You might be interested in
What's the answer to this?
beks73 [17]

Answer:

<em>Q'</em> = (-4, -2)

<em>R' </em>= (4, -2)

<em>S'</em> = (4, 2)

<em>T'</em> = (-4, 2)

Step-by-step explanation:

First, we can create a matrix to scale this rectangle by putting all the x coordinates in the top row and all the y coordinates in the bottom row and multiply it by 4.

Our initial matrix to multiply:

4\left[\begin{array}{cccc}-1&1&1&-1\\-2&-2&-1&-1\end{array}\right]

Moved to the origin:

4\left[\begin{array}{cccc}-1&1&1&-1\\-0.5&-0.5&0.5&0.5\end{array}\right]

Multiplied by four:

\left[\begin{array}{cccc}-4&4&4&-4\\-2&-2&2&2\end{array}\right]

This gives us the points of

<em>Q'</em> = (-4, -2)

<em>R' </em>= (4, -2)

<em>S'</em> = (4, 2)

<em>T'</em> = (-4, 2)

which are our answers.

3 0
2 years ago
0. Juan has been saving for a new bike for two months. So far, he has saved
antiseptic1488 [7]

<u>Given</u>:

Juan has been saving for a new bike for two months. So far, he has saved $150 for the bike.

The money that he has saved so far is 30% of the cost of the bike.

We need to determine the total cost of the bike.

<u>Total cost of the bike:</u>

Let x denote the total cost of the bike.

The total cost of the bike is given by

30\% \ of \ x=150

The value of 30% can be written as \frac{30}{100}

Thus, we get;

\frac{30}{100} \times x=150

Multiplying both sides by \frac{100}{30}, we have;

x=150 \times \frac{100}{30}

Simplifying, we have;

x=\frac{15000}{30}

x=500

Thus, the value of x is 500.

Hence, the total cost of the bike is $500.

3 0
3 years ago
Plz help ASAP!!!!!!!!!!!
forsale [732]
132* as it’s on the same parallel line
7 0
3 years ago
Hey can someone help me?
Viktor [21]
I think it’s (4,2), If not I am so sorry.
8 0
4 years ago
Give me a correct answer, My answer probably wrong.
Georgia [21]

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. dy with the y term and dx with the x term).

\frac{dy}{dx}=\frac{x-1}{3y^2}

3y^2dy=x-1dx

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

y^3=\frac{1}{2}x^2-x+C

Then here, we just solve for y and we have our general solution.

y=\sqrt[3]{\frac{1}{2}x^2-x+C}

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!

3 0
3 years ago
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