When the two waves meet, there are two possibilities:
1.If the waves were both in phase and moving in the same direction, then, the amplitude will double, this is called constructive interference.
2. If the two waves were exactly out of phase, then they will try to move the water surface in all directions, thus, no movement and the waves cancel out. This is called destructive interference.
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Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
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Hello again!
If plants are purebred, then they are homozygous. This means that they have the exact same genes in one pair: for example, AA. If they are both purebred, then the dominant gene will win out every time. The answer for this question, then, would be D. Here is a diagram to help you!
