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timofeeve [1]
2 years ago
5

What is the value of b in this equation? A. -20 B. -6 C. 6 D. 20

Mathematics
2 answers:
kobusy [5.1K]2 years ago
8 0

Answer:

Step-by-step explanation:

a- 12

b- 2

c- 11

and the next part is

x- 6

y- 18

stepan [7]2 years ago
5 0

Answer:

B

Step-by-step explanation:

Using the rules of exponents

(a^m)^{n} = a^{mn}

a^{-m} = \frac{1}{m}

Then

(y^b)^{4} = \frac{1}{y^{24} }

y^{4b} = y^{-24}

Equate the exponents

4b = - 24 ( divide both sides by 4 )

b = - 6 → C

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Marina86 [1]

Answer:

x = 4.5, 4/7

Step-by-step explanation:

To find the roots of a factored equation you need to set the y value at 0, that way you can solve for x. Once you solve for x you get two quantities, which can be graphed. These two quantities are where the x intercepts are.

7 0
3 years ago
What is 6+0<br> plzzzz help
Feliz [49]

6+0=6

When you add any number to 0, that number stays the same since you aren’t adding anything to it. So the answer is 6.

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What is the function equation for the input/output table?
klio [65]

Answer:

3

Step-by-step explanation

Your problem statement tells you  

f(x) passes through point (3, negative 1)

g(x) passes through point (3, negative 1)

This tells you the input value that produces the same output value for the two functions is 3, and that output value is -1.

8 0
3 years ago
A company installs 5000 light bulbs, each with an average life of 500 hours, standard deviation of 100
gulaghasi [49]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x&lt;6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

9x^2-15x=6

Subtract 6 from both sides:

9x^2-15x-6=0

Divide everything by 3:

3x^2-5x-2=0

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0

Find the x using the Zero Product Property:

3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

0 is indeed less than six, so our first correct solution is:

x>-1/3

For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0
3 years ago
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