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3 years ago

Helpppppppppppp on number 19 20 21 22 23

Mathematics

2 answers:

madreJ [45]3 years ago

7 0

19) Q
20) D
21) C
22) C
23) C

Karolina [17]3 years ago

3 0

19.q 20.d 21.6/7 22.6/7 23.b

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How long does it take a cor travelling at 60 mph. to cover 5 miles?

AveGali [126]

Answer:

1 hour and 8 minutes

Step-by-step explanation:

After travelling 1 hour you’ve reached 60 miles. So you go 1 mile/ minute.

You have then 8 miles left. You get: 8 minutes. Which gives us the answer:

1 hour and 8 minutes.

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3 years ago

I need awnsers for questions 1, 3, and 5! WITH WORK PLEASE! GIVING BRAINLYST!

Crazy boy [7]

Answer:

number one is the 45 feet number three is the 12 one i think and five is 70

Step-by-step explanation:

number one is 45 because you basically bring it down to the lowest numbers you can and do the same thing with three and five

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3 years ago

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An advertisement claims a car can go from zero to 60 in 5 seconds. what is the rate of change of the car's speed?

Ugo [173]

Rate of change=(changespeed)/(changetime)=(s1-s2)/(t1-t2)
change is (0-60)/(0-5)=-60/-6=12
answer is 12 units per second

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3 years ago

G(4) =???? Can Someone please help Me on this question

melomori [17]

Answer:

when x=4, the value of y is the answer.

when x=4,we can see that the value of y is 1

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3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

Proof LHS → RHS

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

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3 years ago