Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:
(f+g)(2)
At 
Then
(f+g)(2) = 4
(f-g)(4)
At x = 4
Then
(f-g)(4) = 8
(f ÷g)(2)
At x = 2
Then
(f ÷g)(2) = 7
(f x g)(1)
Then
So
(f x g)(1) = 0
Answer: plane A = 333.33mph
Plane B = 500mph
Step-by-step explanation:
Given data:
Distance between the two planes = 2400miles.
Plane A flew North
Plane B flew south
Solution:
Let v represent plane A.
Let 2v represent plane B.
Distance between the two plane
v + 1.5* v = 3*v
7.5v = 2500miles
v = 333.33mph
Plane B has one and half times the speed of plane A
= 1.5 * 333.33
= 500mph
There's no such thing as parallel or perpendicular "to a point". A problem like that
will always want the new line to be parallel or perpendicular to another <em><u>line</u></em>.
-- If the new line is parallel to the given line, then they have the <em><u>same</u></em> slope.
-- If the new line is perpendicular to the the given line, then the slope of the
new line is [ <em><u>1 / slope of the given line</u></em> ].
In either case, you now have the slope of the new line and a point on it.
From there, you should have no trouble finding its equation.
Answer:
27$
Step-by-step explanation:
Answer:
C. 1 inch = 23 miles
Step-by-step explanation:
To find the scale, add the scale distances shown first.
2.25 + 1.75 = 4 inches on the map
Now, divide the actual mileage (92 miles) by how long it was on the map.
92 / 4
92 = 80 + 12
92/4 = (80/4) + (12/4)
92/4 = 20 + 3
92/4 = 23 miles
That means 1 inch on this map is actually 23 miles. So the scale of the map is 1 inch = 23 miles, which is C.
