Ask question

Ask question

All categories

3 years ago

6

How do i find the slope of a line that passes through a given point and is parallel or perpendicular to another given point?

2 answers:

elena-14-01-66 [18.8K]3 years ago

5 0

There's no such thing as parallel or perpendicular "to a point". A problem like that
will always want the new line to be parallel or perpendicular to another <em><u>line</u></em>.

-- If the new line is parallel to the given line, then they have the <em><u>same</u></em> slope.

-- If the new line is perpendicular to the the given line, then the slope of the
new line is [ <em><u>1 / slope of the given line</u></em> ].

In either case, you now have the slope of the new line and a point on it.
From there, you should have no trouble finding its equation.

tankabanditka [31]3 years ago

5 0

Parallel is same slope.
Perpendicular is same slope but you have make it opposite and flip it.
For example if your slope is 2/3. For Perpendicular it would be - 3/2.

You might be interested in

Tom made fruit punch for a party. He mixed 2 gallons of orange juice, 4 quarts of pineapple juice, 3 pints of cranberry juice, a

Nostrana [21]

Answer:

Try doing 4 eleven one half

Step-by-step explanation:

I not good at this sry

6 0

3 years ago

Read 2 more answers

Would the answer be b an d for this

Paladinen [302]

Answer by answer key by key question equals equation

3 0

3 years ago

Read 2 more answers

Write a function rule. <br><br> y is 9 less than the product of 8 and x.

cluponka [151]

Answer:

dumyemimynumifgmfdhum

3 0

3 years ago

Which of the following shows the correct order of the numbers below? (1/2) 2 , , 0.45

Elodia [21]

The correct order would be 0.45, (1/2), 2
Hope I helped :)

8 0

3 years ago

Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f

Marrrta [24]

Answer:

$\frac{48}{r+9}=\frac{12}{r}$

Step-by-step explanation:

Let r represent Linda's walking rate.

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be $t+9$ miles per hour.

$\text{Time}=\frac{\text{Distance}}{\text{Rate}}$

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

$\text{Time while riding}=\frac{48}{r+9}$

$\text{Time taken while walking}=\frac{12}{r}$

Since both times are equal, so we will get:

$\frac{48}{r+9}=\frac{12}{r}$

Therefore, the equation $\frac{48}{r+9}=\frac{12}{r}$ can be used to solve the rates for given problem.

Cross multiply:

$48r=12r+108$

$48r-12r=12r-12r+108$

$36r=108$

$\frac{36r}{36}=\frac{108}{36}$

$r=3$

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be $t+9\Rightarrow 3+9=12$ miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

7 0

3 years ago