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Helga [31]
3 years ago
6

How do i find the slope of a line that passes through a given point and is parallel or perpendicular to another given point?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
5 0

There's no such thing as parallel or perpendicular "to a point".  A problem like that
will always want the new line to be parallel or perpendicular to another <em><u>line</u></em>.

-- If the new line is parallel to the given line, then they have the <em><u>same</u></em> slope.

-- If the new line is perpendicular to the the given line, then the slope of the
new line is [ <em><u>1 / slope of the given line</u></em> ].

In either case, you now have the slope of the new line and a point on it. 
From there, you should have no trouble finding its equation.


tankabanditka [31]3 years ago
5 0
Parallel is same slope.
Perpendicular is same slope but you have make it opposite and flip it.
For example if your slope is 2/3. For Perpendicular it would be - 3/2.
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3 years ago
Which is the graph of the following equation?
lesantik [10]

Given equation is

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The given equation is in the form of

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2}=1

a^2= 16  , so a=4

b^2 = 9 so b= 4

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So it is a Horizontal hyperbola

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h= 5 and k =2 from the given equation

So center is (5,2)

Now we find vertices

Vertices are (h+a,k)  and (h-a,k)

We know h=5, k=2  and a=4

So vertices are (9,2)  and (1,2)

Second graph having same vertices and center

The correct graph is attached below


7 0
3 years ago
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