Answer:
The ¹³C-NMR Spectrum of <em>tert</em>-butyl alcohol will show only two signals.
(i) Signal at around 31 ppm:
This signal towards upfield is for the carbon atoms which are more shielded and are having rich electron surroundings. The height of peak at y-axis shows the number of carbon atoms as compared to other peaks. In this case it is three times the height of second signal hence, it shows that this peak corresponds to three carbon atoms.
(ii) Signal at around 70 ppm:
This signal towards downfield is for the carbon atom which is more deshielded and is having electron deficient surrounding. As compared to the second signal the height of this peaks corresponds to only one carbon. And the deshielded environment shows that this carbon is directly attached to an electronegative element.
Answer:
Mole Fraction of O2 --> 0.42
Mole Fraction of Ar --> 0.037
Explanation:
Answer: a) 49.8 gram
b) 47.0 %
Explanation:
First we have to calculate the moles of glucose

The balanced chemical reaction will be,

From the balanced reaction, we conclude that
As,1 mole of glucose produce = 2 moles of ethanol
So, 0.54 moles of glucose will produce =
mole of ethanol
Now we have to calculate the mass of ethanol produced


Now we have to calculate the percent yield of ethanol

Therefore, the percent yield is 47.0 %
Q=44.0 ct
p=3.51 g/cm³
Δq=0.200 g/ct
m=q×Δq
v=m/p=q×Δq/p
v=44.0×0.200/3.51≈2.5 cm³
C. 2.5 cm³