Answer: It is because tyrosine kinases and BTK have similar solubilities
Explanation:
In column chromatography, components of a mixture are seperated based on their relative solubilities in two non-mixing phases.
In essence, tyrosine kinases and BTK are present in the eluate due to their similar solubility rates that arise from the similar chemical structure both possess (otherwise it would be impossible for the inhibitor meant for Tyrosine kinase to bind and also inhibits BTK)
Thus, the similar solubilities of both groups is the reason they could elute out of the column without being adsorped.
Convert Mg to grams
1g =1000mg what about 3.91 Mg
= 3.91mg x 1g/1000mg= 3.91 x10^-3 g
moles= mass/molar mass
that is 3.91 x10^-3g /99 g/mol=3.95 x10^-5moles
concentration= moles / vol in liters
that is 3.95 x10^-5/100 x1000= 3.94 x10^-4M
equation for dissociation of CUCl= CUCl----> CU^+ +Cl^-
Ksp=(CU+)(CI-)
that is (3.95 x10^-4)(3.95 x10^-4)
Ksp= 1.56 x10^-7
Answer:
600mL
Explanation:
Molarity of a solution (M) = number of moles (n) ÷ volume (V)
number of moles = mass/molar mass
Molar mass of NaOH = 23 + 16 + 1
= 40g/mol
mole = 30/40
n of NaOH = 0.75mol
Using Molarity = n/V
V = number of moles ÷ molarity
V = 0.75 ÷ 1.25
V = 0.6L
In milliliters (mL), the volume of NaOH will be 0.6 × 1000
= 600mL
