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kiruha [24]
3 years ago
13

Complete the passage to describe how electrons are represented in electron dot diagrams. The maximum number of dots an electron

dot diagram can have is( A:two, B:Four, C:Six, D:Eight) The maximum number of dots drawn on a side of a chemical symbol in an electron dot diagram is ( A:two, B:Four, C:Six, D:Eight)
Chemistry
2 answers:
lyudmila [28]3 years ago
7 0

The maximum number of dots an electron dot diagram can have is <u>EIGHT</u>.

The maximum number of dots drawn on a side of a chemical symbol in an electron dot diagram is TWO.

Please vote Brainliest (:

romanna [79]3 years ago
6 0

D. 8, A. 2

Hope this helps

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Please i need help ……
nasty-shy [4]

Answer:

H2

Explanation:

(l) means liquid

(s) means solid

(g) means gaseous

I hope this helped [:

3 0
2 years ago
49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w
inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The  value is  \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

Explanation:

From the question we are told that

   The volume of the stock solution is  V_1   =  49.9 mL  =  0.0499 \  L  

   The concentration of the stock solution is  C_1  =  0.00292 \  M

   The volume of the diluted solution is  V_2 =  1.00 \  L

   The absorbance is  A =  0.600

Generally the from the titration equation we have that

         C_1 * V_1 =  C_2 * V_2

=>      0.00292  * 0.0499 =  C_2 * 1

=>     C_2 = 0.0001457 \  M

Generally from  Beer's law we have that

      A  =  \epsilon  * l  *  C_2

=>   \epsilon  =  \frac{A}{ l  *  C_2 }

Here  l is the length who value is  1 cm because the unit of  molar  absorptivity coefficient of the dye is M^{-1} *  cm^{-1}

So

            \epsilon  =  \frac{0.600}{ 1   * 0.0001457   }  

=>       \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

4 0
3 years ago
The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti
nadezda [96]

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%

The percentage yield = 83.77%.

7 0
3 years ago
A 74 kg zebra is traveling 15 m/s east. What is the zebra’s momentum
svetoff [14.1K]
Mass × velocity = momentum 

74 x 15 = momentum
7 0
3 years ago
What process describes how plants use air, water, and energy from the Sun to make their own food? A) water.
CaHeK987 [17]

D) the products of photosynthesis.

8 0
3 years ago
Read 2 more answers
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