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liubo4ka [24]
3 years ago
10

How many liters of 10% acid solution should be mixed with 30 liters of a 50% acid solution to get a mix that a 20% acid?

Mathematics
1 answer:
Sonja [21]3 years ago
7 0
The attached diagram shows the QUANTITIES and concentrations of each container. The first container has x liters in it ("how many liters of 10%..."). The second container has 30 liters (and 50% of that is acid). The third container has x + 30 liters (because you dumped the first two containers into the third container), and 20% of that is acid.

Write an equation that shows how the acid adds up:

10% of x plus 50% of 30 equals 20% of (x + 30).

.10x+.50(30)=.20(x+30) \\ .10x+15=.20x+6 \\ 15=.10x+6 \\ 9=.10x \\ 90=x

You should add 90 liters of the 10% solution.

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Answer:

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Step-by-step explanation:

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(6/7)*(1/12)

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vlada-n [284]

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3 years ago
Which statement is true about polynomial 5s^6t^2 + 6st^9 - 8s^6t^2 - 6t^7 after it has been fully simplified?
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Answer:  3t²(2st⁷ - s⁶ - 2t⁵)

<u>Step-by-step explanation:</u>

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2 years ago
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Alenkinab [10]

Answer:

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