Answer:
The interval notation for the domain is
.
Step-by-step explanation:
Consider the provided information.
It is given that 
We need to find the value of
.
Put the value of g(x) in
.
....(1)
Now, put x=x-7 in 



From equation 1.

The domain of the function is the set of input values for which a function is defined.
Here, the value of
should be greater or equal to 0 as the square root of a negative number is not real.
Domain= 
The value of x is all real number greater than
.
Hence, the interval notation for the domain is
.