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Paladinen [302]
3 years ago
8

A box that measures 15 inches by 5 inches by 3 inches.

Mathematics
2 answers:
aleksandrvk [35]3 years ago
7 0

Answer:

225 square inches I think

tino4ka555 [31]3 years ago
6 0

Answer: cubic inches.

Step-by-step explanation: When calculating volume, all of the units must be cubed. And all of the measurements are in inches.

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Which statement is true about the end behavior of the graphed function? (ignore my answer)
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The answer is the first choice:

As the x-values go to positive infinity, the functions values go to negative infinity
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How many ten thousands are in 9,000 tens
mrs_skeptik [129]
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Alex makes ceramic bowls to sell at a monthly craft fair in a nearby city. Every month, she spends $50 on materials for the bowl
Mandarinka [93]
The answer is      p(x) =  25x - 50
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5 0
4 years ago
Solve this question? 7x - 3x +7 =3 (x - 4)+20
Nady [450]
X=1

To solve this you start by adding like terms on the left side and doing the distributive property and adding like terms on the right. This would get you
4x+7=3x+8

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x+7=8

Then subtract 7 from both sides getting x=1.
6 0
3 years ago
Read 2 more answers
The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per
kari74 [83]

Answer:

The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute

P(x⁻>96) =0.0359

Step-by-step explanation:

<em>Explanation</em>:-

<em>Given sample size 'n' =10</em>

<em>mean of the Population = 90 words per minute</em>

<em>standard deviation of the Population =10 wpm </em>

<em>we will use formula</em>

<em>                            </em>Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }<em></em>

<em>Let X⁻  = 96</em>

                           Z = \frac{96-90 }{\frac{10}{\sqrt{10} } }

                          Z =  1.898

<em>The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute</em>

<em></em>P(X^{-}>x^{-} ) = P(Z > z^{-} )<em></em>

<em>                    = 1- P( Z ≤z⁻)</em>

<em>                    = 1- P(Z<1.898)</em>

                   = 1-(0.5 +A(1.898)

                   = 0.5 - A(1.898)

                   = 0.5 -0.4641 (From Normal table)

                  = 0.0359

<u><em>Final answer</em></u>:-

The probability that a random sample of 10 second grade students from  

                = 0.0359

4 0
3 years ago
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