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Alona [7]
3 years ago
12

1. graph the system of inequalities -2x+3y≥ -12 x+y< 3

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0

the answer is y> -2/3+2x/3

Alik [6]3 years ago
6 0

First, convert the equations into slope intercept form.

y=mx+b

Where m is the slope and b is the y intercept.

First equation :

-2x+3y\geq -12 \\ 3y\geq-2x-12\\y\geq-\frac{2}{3}x-4

Second equation :

x+y

So now we graph

y and y\geq-\frac{2}{3}x-4

Since y is less than and not equal to, we shade below the line and the line is dotted.

Since y\geq-\frac{2}{3}x-4 is greater than and equal to, we shade above the line and the line is solid.

And the solutions are anything in the double shaded region.

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If candy cost $5.99 a pound how much would it cost to buy four and a quarter pounds of candy
Degger [83]

Answer:

25.4575

Step-by-step explanation:First since one candy is 5.99 we multiply it by 4 1/4 ponds and then we get $25.4575


7 0
3 years ago
Which expressions are equivalent to 2(b+3c)?
Rina8888 [55]

Answer:

B. (b+3c)+(b+3c)

C. 2(b)+2(3c)

Step-by-step explanation:

we have

2(b+3c)

Distribute the number 2

2(b+3c)=2b+2(3c)=2b+6c

Verify each case

case A) 3(b+2c)

distribute the number 3

3(b+2c)=3b+3(2c)=3b+6c

3b+6c \neq 2b+6c

therefore

Choice A is not equivalent to the given expression

case B) (b+3c)+(b+3c)

Combine like terms

b+3c)+(b+3c)=(b+b)=(3c+3c)=2b+6c

2b+6c= 2b+6c

therefore

Choice B is equivalent to the given expression

case C) 2(b)+2(3c)

Multiply both terns by 2

2(b)+2(3c)=2b+6c

2b+6c= 2b+6c

therefore

Choice C is equivalent to the given expression

6 0
3 years ago
Read 2 more answers
What is a factors for -12
Rzqust [24]

Answer:

4-16= -12

16-28= -12

Step-by-step explanation:

frognj;ghgrue;jnvougheruo'gln

4 0
2 years ago
Need do find the domain and range
Morgarella [4.7K]

Answer:

So

Domain: (-∞,∞)

Range: [-\frac{105}{8} ,∞)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Express cos(27pi/8) as a trigonometric function of an angle in Quadrant I.
Kryger [21]

Answer:

The equivalent trigonometric ratio in Quadrant I is -\cos (\frac{3\pi}{8})

Step-by-step explanation:

The terminal side of \frac{27\pi}{8} is in the 3rd quadrant.

The principal angle is \frac{3\pi}{8}

In other words, the terminal side of \frac{27\pi}{8}  makes an acute angle of \frac{3\pi}{8} radian with the positive x-axis. Acute angles are in the first quadrant.

Since the cosine ratio is negative in the 3rd quadrant,

\cos (\frac{27\pi}{8})=-\cos (\frac{3\pi}{8})

3 0
3 years ago
Read 2 more answers
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