All categories

3 years ago

Which statement is true about the end behavior of the graphed function? (ignore my answer)

Mathematics

1 answer:

hoa [83]3 years ago

7 0

The answer is the first choice:

As the x-values go to positive infinity, the functions values go to negative infinity

You might be interested in

In a sheet metal operation, three identical notches and four identical bends are required. If the operations can be done in any

goldfiish [28.3K]

Answer:

<h2>There are 5040 different possible sequences.</h2>

Step-by-step explanation:

Three identical notches and four identical bends are required in the sheet metal operation.

In total 7 things are required in the metal operation.

We can think it as we need to put the 3 notches and 4 bends in 7 places.

First, lets put the 3 notches in 3 places.

In order to do so, we need to choose 3 places from the 7 places.

We can choose 3 places in $\frac{7!}{3!\times4!} = \frac{5\times6\times7}{6} = 35$ ways.

The 3 notches can be arrange in 3! = 6 ways.

The 4 bends can arrange in 4! = 24 ways.

Thus, in total $35\times24\times6 = 5040$ different possible sequences.

3 0

4 years ago

Please help!! 10 points

hichkok12 [17]

Answer:

We conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{200k^{15}}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

so the expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

first solving

$\sqrt[3]{k^{15}}$

Apply radical rule: $\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\sqrt[3]{k^{15}}=k^{\frac{15}{3}}=k^5$

then solving

$\sqrt[3]{200}$

prime factorization: 200: 2³ · 5²

$=\sqrt[3]{2^3\cdot \:5^2}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt[3]{2^3}\sqrt[3]{5^2}$

Apply radical rule:

$\sqrt[n]{a^n}=a,\:\quad \:a\ge 0$

$=2\sqrt[3]{5^2}$

Thus, the main expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

$=2k^5\sqrt[3]{25}$

Therefore, we conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

3 0

3 years ago

A group of high school students were surveyed about their handedness and their favorite sport. The results are displayed below.

GrogVix [38]

Answer:

The percentage of people who prefer football is approximately the same for the right- and left-handed groups.

Step-by-step explanation:

The bar for the right-handed group representing soccer is between 10% and 20% (below 20%) while the bar for the left-handed group representing soccer is at 20%.

Percentage of left-handed group of people who prefer soccer is higher than the right-handed group who prefer soccer. Therefore, they don't have the same percentage.

6 0

3 years ago

(I BEG U TUTORS HELP) the value if x=9 a solution to the system of equations shown below. Where b is some unknown constant. Dete

Masja [62]

Answer:

b = 43

Step-by-step explanation:

So let's plug things in first:

y= 2x - 20 and y= -5x +b which can become →

2x - 20 = -5x + b (now you said that x=9 so let's plug that in)

2(9) -20 = -5(9) + b (now try solving that)

18 -20 = -45 + b → -2 = -45 + b ( so then add 45 to both sides)

43 = b ( and there's your answer )

7 0

3 years ago

2 ft 12 ft<br><br>what is the surface area and volume

Len [333]

5.12? Maybe 24? I’m sorry if there wrong which they probably are. Sorry :(

4 0

3 years ago