Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
Answer:
The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.
Step-by-step explanation:
Given a function y, the average rate of change S of y=f(x) in an interval
will be given by the following equation:

In this problem, we have that:

Find the average rate of change in the balance over the interval t = 0 to t = 5.


Then

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.
X/a=0.5
y/a=0.5
X+y/a
a=2
X=1
y=1
x+y=a(1)
1+y=2(1)
y=2-1
y=1
7*8-4(6-2)+18
56-4(4)+18
56-16+18
40+18
58
6^2-(8*3)+2^2(7*3)
36-24+4(21)
12+84
96
Answer:
H
Step-by-step explanation:
The parallel line BC divides the sides AD and AE in proportion, that is
=
, that is
=
( cross- multiply )
3AC = 8 ( divide both sides by 3 )
AC =
= 2
, hence
AE = AC + CE
= 2
+ 4 = 6
→ H