WILL GIVE BRIANLIEST

What number must be added to the expression below to complete the square? x² - 18x

kiruha [24]

Answer:

$\boxed {\boxed {\sf 81}}$

Step-by-step explanation:

The standard form of a quadratic is:

$ax^2+bx+c$

To complete the square, the a (leading coefficient) must be 1 and there can only be terms with variables on one side.

The expression given:

$x^2-18x$

follows these rules. Next, we divide the b (linear coefficient) by 2, then square it. Basically:

$(\frac{b}{2})^2$

The b in the expression is -18.

$(\frac{-18}{2})^2$

$(-9)^2= -9*-9= 81$

This is the number that is added.

5 0

3 years ago

three pounds of flour cost $1.65. how much flour do you get per dollar? round your answer to the nearest hundredth.

masha68 [24]

Answer:

1.8181818181818181 etc., which rounds to 1.82

Step-by-step explanation:

1.65/3 = 1/x

3/1.65

4 0

3 years ago

Read 2 more answers

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago

Can someone help me with this ASAP!

asambeis [7]

The following correct answer is c.

This I because when you translate using this, you first start with the point (0,0), translate that point down 3 (-3 means down three when outside parenthesis) and translate it to the right 4 units (this shown in a paraptosis, and when you move to the right you say -4, but if you move to the left you say +4)

4 0

3 years ago

Read 2 more answers

If I run at 7 mph for 1 hr and 30 minutes, how far do I travel

olasank [31]

Answer:

12.5 miles

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers