So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:
i think you grade would go to 69%
Step-by-step explanation:
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that
a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3
the answe is ....
.....
-6,1
step by step
first you sympypfly the answer and then what you want to do is mutyplying te answer by the formula of the graph by then you should already have the table of the formula,then what you want to do is to try to coordinate the number of the graph,AND THA'S HOW YOU GET (-6,1)
Answer:
Suppose N is the size of a population of radioactive atoms at a given time t, and dN is the amount by which the population decreases in time dt; then the rate of change is given by the equation dN/dt = −λN, where λ is the decay constant.
