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qwelly [4]
2 years ago
5

The width of a rectangle is 5 centimeters less than the length . The area of the rectangle is 36 centimeters.find the length?

Mathematics
2 answers:
Iteru [2.4K]2 years ago
7 0

Answer:

9 centimeters

Step-by-step explanation:

Let the width be represented by l - 5, where l is the length.

Use the area formula, A = lw, and plug in l - 5 as w, and 36 as the area. Then, simplify and factor

A = lw

36 = l(l - 5)

36 = l² - 5l

0 = l² - 5l - 36

Factor:

(l - 9)(l + 4)

Set equal to zero and solve for both solutions:

(l - 9)(l + 4) = 0

l - 9 = 0

l = 9

l + 4 = 0

l = -4

The length cannot be negative, so the answer has to be 9.

The length is 9 centimeters

pochemuha2 years ago
6 0
The width of a rectangle is 5 centimeters less than the length . The area of the rectangle is 36 centimeters.find the length?


hope this helps
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Answer:

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3 years ago
A canister is dropped from a helicopter 500m above the ground. Its parachute does not open, but the canister has been designed t
solmaris [256]

Answer:

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

Step-by-step explanation:

A function<em> F</em> is called an antiderivative of <em>f</em> on an interval <em>I</em> if F'(x) = f(x) for all x in <em>I.</em>

Recall that if the object has position function s=f(t), then the velocity function is v(t)=s'(t). This means that the position function is an antiderivative of the velocity function. Likewise, the acceleration function is a(t)=v'(t), so the velocity function is an antiderivative of the acceleration.

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s(t)=\int v(t) \, dt\\s(t)=\int -9.8t \, dt\\s(t)=-4.9t^2+C

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s(t)=-4.9t^2+500=0\\\\-4.9t^2=-500\\\\t^2=\frac{5000}{49}\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\t=\sqrt{\frac{5000}{49}},\:t=-\sqrt{\frac{5000}{49}}

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