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kiruha [24]
3 years ago
9

Which of the following sets of numbers could not represent the three sides of a triangle?

Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

The last one..Number 4

Step-by-step explanation:

When u add the two sides it's supposed to be larger than the bigger side

so 13+20 is smaller than 34

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Simplify 2(3-2i)+5(1+i)
Kipish [7]
11+i
that’s the answer hope it helps:)
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4 years ago
Ms. Barnsley separates her class into two groups. She gives each student the same 25-question math quiz Group A uses a
Anastaziya [24]

Answer:

Step-by-step explanation:

The answer is b trust me

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4 years ago
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The interquartile range (IQR) for the<br>data:<br>32,7,3,-5,1,8<br>, 10,36 is :​
GenaCL600 [577]

Answer:

<em>Your Interquartile range (IQR) would be 19.</em>

Step-by-step explanation:

-5, 1, 3, 7, 8, 10, 32, 36

Median: 7.5

Lower quartile: 2

Upper quartile: 21

Interquartile range: 21 - 2 = 19

7 0
3 years ago
Isabella save 2 nickels today, if she doubles the number of Nicole, she saves every day, how many days, including today, will it
Elden [556K]

Answer:

  8 days

Step-by-step explanation:

On day 8, Isabella will save 256 nickels, bringing her total to 510.

_____

The number of nickels saved on day n is 2^n. The total is 2^(n+1)-2.

_____

The above can be written down from your knowledge of binary sequences. If you want a more formal development, read on.

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The number of nickels saved on day n is a geometric sequence with first term 2 and common ratio 2. The n-th term of the sequence is ...

  an = a1·r^(n-1) = 2·2^(n-1) = 2^n

The sum of n terms of the sequence is ...

  S = a1(r^n -1)/(r -1) = 2(2^n -1)/(2-1)

  S = 2^(n+1) -2

__

We want S > 500, so ...

  500 < 2^(n+1) -2

  502 < 2^(n+1)

  251 < 2^n

  log(251) < n·log(2)

  n > log(251)/log(2)

  n > 7.97 . . . . . . . . 8 days or more to save more than 500 nickels

3 0
4 years ago
What is the inverse of the function f(x) = 2x + 1?
BaLLatris [955]

Answer:

f^{-1} = \frac{x-1}{2}

Step-by-step explanation:

f(x) = 2x+1

<em>Replace it with y</em>

y = 2x+1

<em>Exchange the values of  x and y</em>

x = 2y+1

<em>Solve for y</em>

x = 2y+1

<em>Subtracting 1 from both sides</em>

2y = x-1

<em>Dividing both sides by 2</em>

y = \frac{x-1}{2}

<em>Replace it by </em>f^{-1}

So,

f^{-1} = \frac{x-1}{2}

3 0
4 years ago
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