For the square to fit inside the circle without touching it, the diagonal of the square needs to be less than the diameter of the circle.
Using the Pythagorean theorem we can calculate the diagonal of the square:
X = SQRT(5^2 + 5^2)
X = SQRT(25 + 25)
X = SQRT(50)
X = 7.07
The diagonal of the square is 7.07 cm, which is less than the diameter of the circle, 9cm, so it will fit .
Answer:
m = 10
Step-by-step explanation:
Find 'n' first..... then pythag theorem for 'm'....
n is to 5 as 15 is to n
n/5 = 15/n
n^2 = 75 n = sqrt (75)
Then m^2 = n^2 + 5^2
m^2 = 75 + 25 s-o-o-o-o: m = 10
Answer:
136112 
Step-by-step explanation:
since the outer circle is 25cm wider on one side, the radius of outer circle is 25 cm wider. (imagine rotating the green line to match with the pink line, you'll see the outer circle radius more clearly)
r of inside circle = 148.4/2 = 74.2
r of outside circle = 74.2 +25 = 99.2
the shaded region = A of outer circle - A of inner circle
=3.14(99.2)^2 - 3.14(74.2)^2
area of a circle is
, I plugged in known values above^.
= 30899.6096 - 17287.7096 = 13611.9 (I definitely recommend a calculator)
rounded to nearest whole number = 13612
Answer:
It is C, in my opinion. Have a nice day. :)
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
count