The train would have traveled 40 degrees around the track.
Take 40.00 divide by 8 to pay 5.00 a bag
Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.
I don't believe that there is a limit
If f = {(4, 2), (6, 1), (8, 4), (10, 2), (12, 5)}, what is the range
UNO [17]
Answer:
Range = {2,1,4,5}
Step-by-step explanation:
When a function is given in the form if a relation. i.e. ordered pairs.
When the function is given in the form of ordered pairs then the set of first elements i.e. x-coordinates of all ordered pairs forms domain while the set of second elements i.e. y-coordinate of all ordered pair is called range.
So in the given function:
Range = {2,1,4,5}
The repeating values are only written once..