All categories

2 years ago

Helpppp! please i'll put brainliest

Mathematics

2 answers:

Anna35 [415]2 years ago

4 0

Answer: -1

Step-by-step explanation:

Subtract each fraction by each other than simplify

Tasya [4]2 years ago

4 0

Answer:

= 11 /10

decimal : 1.1

Step-by-step explanation:

You might be interested in

Write 2.9687 in p/q form , where p and q are integers and q is non zero

Anna35 [415]

Answer:

Step-by-step explanation:

2.9687= $\frac{29687}{10000}$

4 0

3 years ago

Two types of barrel units were in use in the 1920s in the united states. the apple barrel had a legally set volume of 7056 cubic

r-ruslan [8.4K]

1.) 7,056 * 41 = 289,296 (apple barrel volume * no. of barrels sold)
5,826 * 41 = 238,866 (cranberry barrel volume * no. of barrels sold)

2.) Subtract cranberry barrel volume from apple barrel volume
289,296 - 238,866 = 50,430 cubic inches

3.) Convert 50,430 cubic inches to liters
50,430 = 826.39 liters or 826.40 liters (rounded off)

4.) Therefore, 826.40 liters is the discrepancy in the shipment volume.

3 0

3 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

Find the surface area of this net.

Elden [556K]

Answer:

Step-by-step explanation:

First, let's find the surface area of both the triangles

5x3=15

So, the surface area of the triangles is 15 sq.cm

Now, let's find the surface area of the base (large rectangle in the middle)

12x8=?

10x8=80

2x8=16

80+16=96

12x8=96

So, the surface area of the base, is 96sq.cm

Now, let's find the surface area of both of the side rectangles

12x5=60

60x2=120

So, the surface area of the two side rectangles is 120sq.cm

Now, let's find the total surface area by adding all of our answers.

120+96=216

216+15=231

<h2>So hence, the surface area of this net is 231cm²</h2>

3 0

2 years ago

Mrs. Hetler took her tour guide group on a trip that was 3 miles long. If they stopped

KiRa [710]

Answer:6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers