2(c-3)=s
because you have to subtract 3 years from sherman's age first, so you need the parentheses
Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
So what I would do is first multiply the mean by 4 and that is the total u need, 146.5, to have a mean of 36 and 5/8. Next I add the lengths given, which is 110.625, and then I would subtract it from 146.5 which is 35.875 which is 35 and 7/8. You can also check the answer by finding the mean of the 4 numbers and determining if it comes out to 36 and 5/8. The answer is C. Hope this helps!
