Question

Assume a quarter, diameter 0.96 inches, is centered at the point (–2, 5), where each unit represents one inch. Write the equation of a circle that would precisely enclose the coin.

Answer 1

Answer:

$(x+2)^{2}+(y-5)^{2}=0.2304$

Step-by-step explanation:

we know that

The equation of a circle into center radius form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

$r=Diameter/2=0.96/2=0.48\ in$

$(h,k)=(-2,5)$

substitute

$(x+2)^{2}+(y-5)^{2}=0.48^{2}$

$(x+2)^{2}+(y-5)^{2}=0.2304$