I don’t know the answer

Mathematics

1 answer:

masya89 [10]3 years ago

4 0

Answer:

?=1O or 15

Step-by-step explanation:

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A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walkercharge for a 45 minute w

leonid [27]

hello

from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.

we can write out an equation in function notation

let the number of hours be represented by x

$f(x)=6+30x$

now we can proceed to solve the cost of the walk for 45 minutes

$\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}$

now we can input the value into the equation and know the cost for 45 minutes walk

$\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}$

from the calculation above, the cost of 45 minutes walk will cost $28.5

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1 year ago

Lisa paid $48.25 for 16.7 gallons of gasoline. What was the cost per gallon, rounded to the nearest

vlabodo [156]

$2.89 Just do the cost divided by the gallons and round up.

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3 years ago

three adults and four children must pay $107. two adults and three children must pay $76. find the price of the adult ticks and

jenyasd209 [6]

Assigning "a" as cost of adult tickets and "c" the cost of children's tickets.

3a + 4c = 107
2a + 3c = 76

elimination method
2(3a + 4c = 107)
-3(2a + 3c = 76)

6a + 8c = 214
-6a - 9c = -228
----------------------
0 - c = - 14
c = 14

Then 2a + 3(14) = 76
2a = 76 - 42
2a = 34
a = 34/2
a = 17

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3 years ago

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morpeh [17]

Answer:

${ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}$

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2 years ago

1. Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is NOT replaced before selecting the sec

Oduvanchick [21]

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3 years ago