1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WARRIOR [948]
3 years ago
15

Where was hydrogen discovered

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer:

maybe greece

Explanation:

by henry cavendish in 1766

You might be interested in
If the methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume w
Sunny_sXe [5.5K]

116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C that was extracted and placed under STP conditions.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

The solubility of methane in water at 25 degrees Celcius is 1.3 x 10^{ -3} M. It implies   1.3 x 10^{ -3} moles of methane are dissolved in one litre of water.

The number of moles of methane in 4 L of water can be calculated as follows:

Moles of methane = \frac{1.3 . 10^{ -3} }{1L} x\frac{4L}{1L}

Moles of methane = 5.2 x 10^{ -3}

STP refers to standard temperature and pressure. Under STP conditions, the temperature of the substance is  0 degrees celcius and its pressure is 1 atm.

An ideal gas is an imaginary gas comprising of a large number of randomly moving particles and the motion between such articles is considered to be perfectly elastic. The ideal gas equation describes the relationship between pressure, volume, temperature and number of moles of a gas.

The expression for ideal gas equation is as follows:

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1 atm

V= ?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=273K

n=?

Putting value in the given equation:

\frac{PV}{RT}=n

5.2 x 10^{ -3} = \frac{1 \;atm\; X \;V}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 273}

V= 116.6 x 10^{ -3}

Hence, 116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

4 0
2 years ago
How does temperature affect the vapor pressure of a liquid?
Mamont248 [21]

Answer:

As the temperature of a liquid increases, the kinetic energy of its molecules also increases. As the kinetic energy of the molecules increases, the number of molecules transitioning into a vapor also increases, thereby increasing the vapor pressure.

3 0
3 years ago
The molar mass of an unknown gas was measured by an effusion experiment. It was found that it took 60 s for the gas to effuse, w
Marizza181 [45]

Answer:

The molar mass of the gas is 44 g/mol

Explanation:

It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:

\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }

If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):

\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }

6,61 = √M₂

44g/mol = M₂

<em>The molar mass of the gas is 44 g/mol</em>

<em></em>

I hope it helps!

4 0
3 years ago
Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0
3 years ago
what is the consequence on your brain for snorting or taking amphetamines(meth/stimulant) as a 16 year old(minor)?
Yanka [14]

There are many consequences!

Some being:

* ADDICTION

* HEALTH ISSUES

* MENTAL ISSUES

5 0
3 years ago
Read 2 more answers
Other questions:
  • How many grams of chlorine gas are in a 17.8 liter sample at 1.1 atmospheres and 29 degrees Celsius
    7·1 answer
  • Enter the complete ionic equation to show the reaction of aqueous lead(ii) nitrate with aqueous potassium sulfate to form solid
    15·1 answer
  • What happens when 2 protons go near eachother
    10·1 answer
  • Why would a table be more suitable than a graph to show data
    12·1 answer
  • Tertiary alcohols with two identical alkyl groups attached to the alcohol carbon can be made either from an ester and two moles
    12·1 answer
  • Donde se pueden encontrar un río biejo​
    13·1 answer
  • What is Hess‘s law please help
    7·1 answer
  • PORFA AYUDAA !!!
    6·1 answer
  • Need some URGENT HELP please
    14·1 answer
  • Which organisms use cellular respiration as a way to convert energy into usable form?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!