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crimeas [40]
3 years ago
9

If an unknown solution has a pH of 9, what is that solution classified as?

Chemistry
2 answers:
fomenos3 years ago
8 0

Answer:

option A is the ans i think so

omeli [17]3 years ago
5 0

Answer:

Explanatioidkn:

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What is the madd in grams of 0.40 moles of sodium borohydride, NaBH4
Orlov [11]

Answer:

Mass = 15.1 g

Explanation:

Given data:

Number of moles of NaBH₄ = 0.40 mol

Mass in gram = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of NaBH₄ = 37.83 g/mol

By putting values,

Mass = 0.40 mol × 37.83 g/mol

Mass = 15.1 g

3 0
3 years ago
Give Me a simple definition for Acids.
levacccp [35]

Answer:

an acid is a substance which produces hydrogen ions as the only as the only positive ion when dissolved in water.

8 0
2 years ago
Identify the type of chemical reaction of cobalt (III) fluoride
zysi [14]

The compound crystallizes in the aluminium trifluoride motif. Each fluoride is a doubly bridging ligand. The cobalt centers are octahedral.


CoF3 decomposes upon contact with water to give oxygen:


4 CoF3 + 2 H2O → 4 HF + 4 CoF2 + O2

It reacts with fluoride salts to give the anion [CoF6]3−, which is also features high-spin, octahedral cobalt(III) center.

4 0
4 years ago
Each equation is incorrect. find the errors, then rewrite and balance each equation. cl2 + nai → nacl2 + i nh3 → n + h2 na + o2
VikaD [51]
1) Balanced chemical reaction: Cl₂ + 2NaI → 2NaCl + I₂.
Chlorine and iodine are diatomic molecules.
2) Balanced chemical reaction: 2NH₃ → N₂ + 3H₂.
Nitrogen and hydrogen are diatomic molecules.
3) Balanced chemical reaction: 4Na + O₂ → 2Na₂O.
Sodium in compounds has oxidation number +1 and oxygen -2.
6 0
4 years ago
Suppose you find a rock that contains some potassium-40 (half-life of 1.3 billion years). you measure the amount and determine t
Alborosie
Equation for Half life :
A = a(0.5)^(t/h)
A is current amount, "a" is initial amount, h is halflife, t is time

5 = 40(0.5)^(t/1.3x10^9)
5/40 = (0.5)^(t/1.3x10^9)
take the log of both sides , power rule
Log(5/40) = (t/1.3x10^9) * Log(0.5)
(1.3x10^9) * Log(5/40) / Log(0.5) = t
3.9x10^9 years = t

And if you think about what a half life is, the time it take for the amount to reduce to half.
40/2 = 20
20/2 = 10
10/2 = 5
It went through 3 half-lifes
3 * 1.3x10^9 = 3.9x10^9 years

7 0
3 years ago
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