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Leya [2.2K]
3 years ago
5

What will be the the net ionic equations for the following ones:- a) AgNO3 + KCl b) Ni(NO3)2 + Na2S c) CaCl2 + Na2CO3. 2) Write

out the total ionic equation and cancel anything that is common on both sides Ca+2(aq) + 2Cl-(aq) + 2Na+(aq) + CO3-2(aq) --> CaCO3(s) + 2Na+(aq) + 2Cl-(aq)
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
4 0
In a) the final equation is AgNO3 + KCl = AgCl + KNO3, b) Ni(NO3)2 + Na2S = 2NaNO3 + NiS; c) CaCl2 + Na2CO3 = 2 NaCl + CaCO3. In 2) The total net equation is Ca 2+ + CO32- = CaCO3 (s). 
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Which one of the following equations is properly balanced? a. CH 3CHO + 3O 2 → 2CO 2 + 2H 2O b. NH 4NO 3 → 2H 2O + N 2 c. Na 2CO
Gennadij [26K]

Answer:

The chemical equation that is properly balanced is;

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Explanation:

To solve the question, we note the reactions thus and we look for a reason why the reaction is not balanced as follows.

a. CH₃CHO + 3O₂ → 2CO₂ + 2H₂O

Here we have 7 oxygen atoms in the reactant and 6 in the products

Not balanced

b. NH₄NO₃ → 2H₂O + N₂

Here we have three oxygen in the reactant and four in the products = Not balanced

c. Na₂CO₃ + 2H₂SO₄ → Na₂SO₄ + 2H₂O + CO₂

Here we have 11 oxygen atoms in the reactant and 8 in the products = Not balanced

d. 2Na₂SO₄ + 3Bi(NO₃)₃ → Bi₂(SO 4)₃ + 9NaNO₃

Here  we have 2 Na in the reactants and 9 Na in the products = Not balanced

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Here we have equal number of products and reactants = Balanced chemcal reaction equation.

3 0
2 years ago
Which element is always present in a combustion reaction?
diamong [38]
The element <u>Oxygen</u> is always present in a combustion reaction.
4 0
3 years ago
Read 2 more answers
This is the chemical equation for the production of ammonia (chemical formula: NH3) from Nitrogen and Hydrogen (N2 and H2):
scoray [572]

Answer:

Honestly, I'm not even sure what the incorrect student was trying to do. The correct answer is:

( ) = the number of elements

(1)N2 and (3)H2

I think the student added the N2 and H2 to "balance" the chemical equation when instead they should have tried the balance the equation by making sure the atoms on the reactant side are equal to the atoms on the product side. You do this by multiplying the atoms on the reactant side until they equal the product side (not by adding them, as the student did).

8 0
2 years ago
A 0.327-g sample of azulene (C10H8) is burned in a bomb calorimeter and the temperature increases from 25.20 °C to 27.60 °C. The
liq [111]

Explanation:

The given data is as follows.

Molecular weight of azulene = 128 g/mol

Hence, calculate the number of moles as follows.

      No. of moles = \frac{mass}{\text{molecular weight}}

                            = \frac{0.392 g}{128 g/mol}

                            = 0.0030625 mol of azulene

Also,    -Q_{rxn} = Q_{solution} + Q_{cal}

       Q_{rxn} = n \times dE

         Q_{solution} = m \times C \times (T_{f} - T_{i})

              Q_{cal} = C_{cal} \times (T_{f} - T_{i})

Now, putting the given values as follows.    

     Q_{solution} = 1.17 \times 10^{3} g \times 10^{3} \times 4.184 J/g^{o}C \times (27.60 - 25.20)^{o}C

                   = 11748.67  J

So,  Q_{cal} = 786 J/^{o}C \times (27.60 - 25.20)^{o}C

                    = 1886.4 J

Therefore, heat of reaction will be calculated as follows.

        -Q_{rxn} = (11748.67 + 1886.4) J

                      = 13635.07 J

As,  Q_{rxn} = n \times dE

          13635.07 J = -n \times dE

                dE = \frac{13635.07 J}{0.0030625 mol}

                     = 4452267.75 J/mol

or,                 = 4452.26 kJ/mol       (as 1 kJ = 1000 J)

Thus, we can conclude that \Delta E for the given combustion reaction per mole of azulene burned is 4452.26 kJ/mol.

7 0
3 years ago
Facial dimples in man are dominatant over no dimples. Show
Nat2105 [25]
I'm assuming false but really have no clue
3 0
3 years ago
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