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xeze [42]
3 years ago
7

Can someone fact check this to make sure its correct

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
5 0

All your answers look good!

Stella [2.4K]3 years ago
5 0

Answer:

looks good

Step-by-step explanation:

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PLEASE HURRY WITH THIS
Snezhnost [94]

Answer:

Step-by-step explanation:

100.5 in ^2

5 0
3 years ago
Over which interval is the function increasing
leva [86]

Answer: I THINK A function f (x) is called increasing in an interval [a,b] when f' (x) > 0 in the interval (a,b). That is, in that interval, with increasing the value of x the value of f (x) increases. Let f (x) be the function which is shown in the given diagram.

Step-by-step explanation:

7 0
2 years ago
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Factorise 3ab²+15a²b³+21a³b²​
evablogger [386]

Given:

The expression is

3ab^2+15a^2b^3+21a^3b^2

To find:

The factor form of the given expression.

Solution:

We have,

3ab^2+15a^2b^3+21a^3b^2

Taking out the common factors, we get

3ab^2(1+5ab+7a^2)

It is clear that (1+5ab+7a^2) cannot be factories further.

Therefore, the factorized form of the given expression is 3ab^2(1+5ab+7a^2).

5 0
3 years ago
HeLLLLpppPpp me please
stiv31 [10]

Answer:

5 3/4

Step-by-step explanation:

4 0
3 years ago
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Allan purchased $135,000 of 10 year life insurance @ $4.55 per $1000, at age 35. what will be his total premiums over the 10 yea
andriy [413]
Given, 
Policy Value = $135000 
Duration = 10 years 
Premium= $4.55 per 1000 per year  
Calculation, 
So, yearly premium for $135000 = (4.55/1000)*135000 = 614.25  
So, premium over 10 years for $135000 = 614.25*10 = $6142.5  
Answer. Total premium over 10 years that Allan will have to pay = $6142.5
7 0
4 years ago
Read 2 more answers
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