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2 years ago

Determine if you would use <, >, or = to complete the statement:

Mathematics

1 answer:

Virty [35]2 years ago

4 0

I’ll answer this later but use an equation 180 degrees

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Match the vocabulary to the correct operation PLZ ANSWER:(

MaRussiya [10]

Product=multiplication
Sum=addition
Difference=subtraction
Quotient=division
Quantity=parentheses

4 0

3 years ago

A car used 1/48 of a gallon of gas to drive 1/4 of a mile . At this rate , how many miles can the car travel using 1 gallon of g

sveticcg [70]

Answer:

12 miles

Step-by-step explanation:

Your car uses 1/12th of its entire gas to go a single mile. This means that you need to drive 12 miles to run out of gas.

4 0

2 years ago

Read 2 more answers

HELP ASAP FIND AREA PLZ

lesantik [10]

9×18 rectangle plus a (18-6-6)×4 right triangle

Area = 9×18 + (1/2)×6×4 = 174

Answer: 174 sq ft

7 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago

If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i

navik [9.2K]

Answer: 37 units

Step-by-step explanation:

$Blue=144units^2$ This also works as the height of the triangle.

$Pink=1225units^2$ This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

$Formula: A=s^2$

$s=\sqrt[]{A}$

Let's work with Blue.

$s=\sqrt[]{144units^2} \\s=12units$

Now Pink.

$s=\sqrt[]{1225units^2}\\s=35units$

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

$c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units$

7 0

3 years ago