Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
−
3
2
+
7
+
2
0
-3y^{2}+7y+20
−3y2+7y+20
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}-7y-20)
−1(3y2−7y−20)
2
Use the sum-product pattern
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
−1(3y2−7y−20)
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
−1(3y2+5y−12y−20)
3
Common factor from the two pairs
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+5y-12y-20)
−1(3y2+5y−12y−20)
−
1
(
(
3
+
5
)
−
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
−1(y(3y+5)−4(3y+5))
4
Rewrite in factored form
Solution
−
1
(
−
4
)
(
3
+
5
)
7/8 yrds of ribbon per bow
if you need 4 bows
7/8 x 4 = 28/8 = 3 1/2 yards of ribbon needed
Answer:
a diagram in which the numerical values of variables are represented by the height or length of lines or rectangles of equal width.
Step-by-step explanation:
Answer:
29 units²
Step-by-step explanation:
You could divide this into two triangles and two trapezoids to find the area. But since the majority of these are either whole or half squares, I‘d count those. Then you’d just have one triangle in the top right corner.
Whole squares: 21
Half Squares: 10 (so 4 square units)
Triangle: 1/2(b)(h)=1/2(5)(2)=5
TOTAL = 21+4+5= 29 units²
