Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
In order to find the second endpoint or a line segment given the first and the midpoint, you need to realize that the midpoint is an average of the two endpoints. Given that fact, we can derive this formula looking at x values of points A and B with midpoint M. Remember this is only looking at the x values.
(A + B)/2 = M
So if we are looking for A, we can solve for A and use this modified formula.
(A + B)/2 = M
A + B = 2M
A = 2M - B
Now we can do this with the y values of these points as well. We then have the coordinates of both parts of A.
There are 2 way to solve this.
one using Pythagoras theorem and 2nd using trigonometry
so lets solve it by both
using Pythagoras theorem we know
base^2 + perpendicular^2 = hypotanes^2
6^2 + x^2 = 12^2
36 + x^2 = 144
x^2 = 144- 36 = 108
x = √(108) = √( 2×2×3×3×3)
= (2×3) √ (3) = 6 √3
so answer is option 2
bow lets use trigonometry
we know
sin theta = perpendicular / hypotanes
sin 60 = x /12
x = 12 × sin 60
we kNow sin 60 = √3/ 2
so
x = 12×√3 /2 = 6√3
More information is needed to solve the problem.
