Answer:
d
Step-by-step explanation:
Δ OPG is right with hypotenuse OG being the radius of the circle
Using Pythagoras' identity in the right triangle
OG² = OP² + PG²
[ PG = 11 , since OP is the perpendicular bisector of FG ]
OG² = 8² + 11² = 64 + 121 = 185
Δ OQS is right with hypotenuse OS being the radius
Using Pythagoras' identity
OS² = QS² + OQ² , that is
185 = 13² + x²
185 = 169 + x² ( subtract 169 from both sides )
16 = x² ( take the square root of both sides )
4 = x → d
340 = 255
100 = ?
100 times 255 = 25500
25500 divided by 340 is 75
75 ltrs
Answer:
y = 65
Step-by-step explanation:
45 + 57 = x + y
x = 37
45 + 57 = 37 + y
45 + 57 = 102
102 = 37 + y
102 = 37 + y
-37 -37
102 - 37 = 65
37 + y - 37 = y
65 = y
y = 65
Answer:
![D(x)= x\sqrt{2}](https://tex.z-dn.net/?f=D%28x%29%3D%20x%5Csqrt%7B2%7D)
Step-by-step explanation:
Given
![Side = x](https://tex.z-dn.net/?f=Side%20%3D%20x)
Required
Represent the diagonal as a function
Using Pythagoras theorem, the diagonal is:
![D^2= Side^2 + Side^2](https://tex.z-dn.net/?f=D%5E2%3D%20Side%5E2%20%2B%20Side%5E2)
Substitute x for Side
![D^2= x^2 + x^2](https://tex.z-dn.net/?f=D%5E2%3D%20x%5E2%20%2B%20x%5E2)
![D^2= 2x^2](https://tex.z-dn.net/?f=D%5E2%3D%202x%5E2)
Take the square root of both sides
![D= \sqrt{2x^2](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B2x%5E2)
Split
![D= \sqrt{2} * \sqrt{x^2](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B2%7D%20%2A%20%5Csqrt%7Bx%5E2)
![D= \sqrt{2} * x](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B2%7D%20%2A%20x)
![D= x\sqrt{2}](https://tex.z-dn.net/?f=D%3D%20x%5Csqrt%7B2%7D)
Express as a function.
![D(x)= x\sqrt{2}](https://tex.z-dn.net/?f=D%28x%29%3D%20x%5Csqrt%7B2%7D)