3 years ago

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Mathematics

1 answer:

AURORKA [14]3 years ago

8 0

Answer:

dang....................

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Factor Completely.<br> 30r^2 + 30r + 75.

kari74 [83]

Answer:

15(2r^2+2r+5)

Step-by-step explanation:

I'm more of a guess and check type of person, but 15 x 2r^2 = 30r^2, 15 x 2r = 30r, and 15 x 5 = 75

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3 years ago

The solids are similar. Find the volume V of the larger solid.

diamong [38]

Answer:

9604

Step-by-step explanation:

V = (7/3)³ × 756

= 343/27 × 756

= 9604 ft³

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2 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

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2 years ago

Solve for n.<br> Q=5n+5z

kirill115 [55]

$q=5n+5z\ \ \ \ \ \ \ |subract\ 5z\\\\q-5z=5n\ \ \ \ \ \ \ |divide\ by\ 5\\\\n=\frac{q-5z}{5}\\\\Answer\ is\ n=\frac{q-5z}{5}$

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3 years ago

Read 2 more answers

Let x represent any year. Write an inequality in terms of x and 453 that is true only for values of x that represents years afte

Elis [28]

Try google I’m sorry I don’t know

8 0

3 years ago