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LUCKY_DIMON [66]
3 years ago
13

All the radioactive elements are found in the last group of the Periodic Table.

Chemistry
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

False

Explanation:

faust18 [17]3 years ago
4 0
I think the awser is false
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Which statement implies that some ethanol supporters have changed their minds about the fuel?
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Answer:

D. “Many people are disappointed in ethanol because they believed that it would help reduce the price at the pump, not increase it.”

Explanation:

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A glass of water sitting in direct sunlight evaporates over time. Explain this phase change in terms of the types of heat transf
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3 years ago
This diagram shows the basis for forming which of the following
Elza [17]

(I didn't have this as a question on any of my quizzes, but I will try my best. I wish you luck!)

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5 0
2 years ago
Cu(s) + 4 HNO3 (aq) --&gt; Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O(l)
GREYUIT [131]

Answer:

The percent by mass of copper in the mixture was 32%

Explanation:

The ammount of HNO₃ used is:

mol HNO₃ = volume * concentration

mol HNO₃ = 0.015 l * 15.8 mol/l

mol HNO₃ = 0.237 mol

According to the reaction, 4 mol HNO₃ will react with 1 mol Cu and produce 1 mol Cu²⁺. Since we have 0.237 mol HNO₃, the amount of Cu that could react would be (0.237 mol HNO₃ * 1 mol Cu / 4 mol HNO₃) 0.06 mol. This reaction would produce 0.060 mol Cu²⁺, however, only 0.010 mol Cu²⁺ were obtained, indicating that only 0.010 mol Cu were present in the mixture. This means that the acid was in excess, so we can assume that all copper present in the mixture has reacted.

Since 0.010 mol of Cu²⁺ were produced, the amount of Cu was 0.01 mol.

1 mol of Cu has a mass of 63.5 g, then 0.01 mol has a mass of:

0.01 mol Cu * 63.5 g / 1 mol = 0.635 g.

Since this amount was present in 2.00 g mixture, the amount of copper in 100 g of the mixture will be:

100 g(mixture) * 0.635 g Cu / 2 g(mixture) = 32 g

Then, the percent by mass of Cu (which is the mass of Cu in 100 g mixture) is 32%

6 0
3 years ago
Read 2 more answers
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