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3 years ago

True or false adding a solute to a solvent will raise the freezing point of the solvent.

Chemistry

1 answer:

sergejj [24]3 years ago

8 0

It would be false adding a solute to a solvent

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One of the most difficult solar energy design problems to solve is:

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I'm not sure but i would say C.storing the heat energy.

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How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

olganol [36]

Answer: 127.5ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HNO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL$

Putting values in above equation, we get:

$1\times 0.5\times V_1=1\times 0.75\times 85\\\\V_1=127.5mL$

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

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3 years ago

Define the terms octet rule.

luda_lava [24]

Answer:

The octet rule is a chemical rule of thumb that reflects the theory that main-group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas.

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2 years ago

A 1.0 L container holds a sample of hydrogen gas at 300 K and 101.5 k Pa. If the pressure increases to 508 k Pa and the volume r

ankoles [38]

Answer: The temperature will be 1501.47 K.

Explanation:

To calculate the temperature of the gas when pressure is increased, we use the equation given by Gay-Lussac's Law.

This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

Mathematically,

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and initial temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and final temperature of the gas.

We are given:

$P_1=101.5kPa\\T_1=300K\\P_2=508kPa\\T_2=?K$

Putting values in above equation, we get:

$\frac{101.5kPa}{300K}=\frac{508kPa}{T_2}\\\\T_2=1501.47K$

Hence, the temperature will be 1501.47 K

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3 years ago

Wha characteristic of metallic bonds allow metals to be malleable and ductile

ANTONII [103]

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