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3 years ago

True or false adding a solute to a solvent will raise the freezing point of the solvent.

Chemistry

1 answer:

sergejj [24]3 years ago

8 0

It would be false adding a solute to a solvent

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Why pie bond are not perticipate in hybridaization

DedPeter [7]

The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.

3 0

3 years ago

Solid to Gas

miskamm [114]

Answer:

c. c. c c c c c cçcc. ccccccccc

Explanation:

ccc cc

7 0

3 years ago

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

3 years ago

Assume that Na+ is being transported across a membrane via facilitated diffusion. Which of the following conditions would allow

lesya [120]

Answer:

<h2>4. Na+ diffusing toward the side of the membrane with Cl− and 50% less Na+.</h2>

Explanation:

Facilitated diffusion is a type of transport mechanism in which the special proteins are involved and play an important role in the transport of the atoms, ions or molecules. This mechanism is based on the electrochemical gradient differences. When this difference increase, then the transport of the sodium takes place because sodium ions are chemically attracted by chloride ions. In a facilitated diffusion process, no energy requirement takes place. This process occurs along the concentration gradient.

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4 years ago

Question 2 how many valence electrons are in a neutral atom of silicon

marshall27 [118]

Si -Atomic number -14 -1s2 2s2 2p6 3s2 3p2 - 4 valence electrons

7 0

3 years ago