Answer:
c = 0.898 J/g.°C
Explanation:
1) Given data:
Mass of water = 23.0 g
Initial temperature = 25.4°C
Final temperature = 42.8° C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of water is 4.18 J/g°C
ΔT = 42.8°C - 25.4°C
ΔT = 17.4°C
Q = 23.0 g × × 4.18 J/g°C × 17.4°C
Q = 1672.84 j
2) Given data:
Mass of metal = 120.7 g
Initial temperature = 90.5°C
Final temperature = 25.7 ° C
Heat released = 7020 J
Specific heat capacity of metal = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.7°C - 90.5°C
ΔT = -64.8°C
7020 J = 120.7 g × c × -64.8°C
7020 J = -7821.36 g.°C × c
c = 7020 J / -7821.36 g.°C
c = 0.898 J/g.°C
Negative sign shows heat is released.
Compact fluorescent bulbs because they made out of glass that will break and will dye and then they can't be used again
Answer:
osmosis is a process where by solvent or fluid molecules flow from low concentration to high concentration.
So in
A.solvent will flow from B to A because
B = 3.45 M sodium bromide is more concentrated than 3.45 M calcium iodide;
b) solvent still flow from B to A because
A = 5.00 M sucrose is less concentrated than B = 3.00 M potassium nitrate
Answer:
the action or power of focusing one's attention or mental effort.
Explanation:
Answer: Filtration
Explanation:
Heterogeneous mixtures : It is a mixture that has non-uniform composition throughout the solution and the particle size or shapes are also different. There is a physical boundary between the dispersed phase and dispersion medium.
Homogeneous mixtures : It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different. There is no physical boundary between the dispersed phase and dispersion medium.
Filtration is a type of mechanical separation process in which the smaller particles are separated from the bigger particles through the filter paper where small particles pass through the fine holes of filter paper and the left ones remain on the filter paper.