Recall that to compute for the new amount of the original sum at a compound interest is
A(t) = P(1 + r/n)^(nt)
where P is the original amount, r is the interest rate, n is the number of times P is compounded each year, and t is the number of year.
With this, the total amount owed by Sam in five full years becomes [(120)(1 + 0.30/12)^60 ]. The total interest is the difference between the original amount owed and the amount that needs to be paid over time. Thus, total interest is [(120)(1 + 0.30/12)^60 ] - 120 = 407.97.
Therefore, the total interest is $407.97<span>.</span>
I’m guessing it’s going to be third power
1 and a half times because 10 goes in to 25 two times but 10 can't go into 25 so you will get 5 left and 10 - 5 is 5 and 5 tenth makes a half so the answer is,
1 and a half times
<u>1</u><u>.</u><u> </u><u>(ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0</u>
We know that (a+b)(a-b) = a²-b²
(ab + bc)(ab -bc) can be written as a²b² - b²c²
(bc + ca)(bc -ca) can be written as b²c² - c²a²
(ca + ab)(ca - ab) can be written as c²a² - a²b²
→ a²b² - b²c² + b²c² - c²a² + c²a² - a²b²
→ a²b² - a²b² - b²c² + b²c² - c²a² + c²a²
→ 0
<u>2</u><u>.</u><u> </u><u>(a + b + c) (a² + b² + c² – ab – bc – ca) = a³ + b³+ c³ – 3abc</u>
→ a³ + ab² + ac² -a²b - abc -ca² + a²b + b³ + bc² - ab² - b²c - abc + a²c + b²c + c³ - abc - bc² - c²a
→ a³ + b³+ c³ + (- abc - abc - abc) + (ab² - ab² )+ (ac² - ca² ) -(a²b + a²b )+ (bc² - bc² )+ (a²c - c²a) + (b²c - b²c)
→ a³+b³+c³ - 3 abc .
<u>3</u><u>.</u><u> </u><u>(p – q) (p² + pq + q²) = p³ – q³. </u>
→ p³ + p²q + pq² - p²q - pq² - q³
→ p³ - q³ +(p²q - p²q) + (pq² - pq²)
→ p³ - q³
Answer: inequality
Step-by-step explanation:
An <u>inequality</u> is a sentence that uses the symbols >, <, ≥, ≤, or ≠ to show a relationship. Here are some different inequalities for an example:
6 < 11
7 > 2
12.5 ≠ 13.5
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