Solve for x:
10 (x + 2) = 5 (x + 8)
Expand out terms of the left hand side:
10 x + 20 = 5 (x + 8)
Expand out terms of the right hand side:
10 x + 20 = 5 x + 40
Subtract 5 x from both sides:
(10 x - 5 x) + 20 = (5 x - 5 x) + 40
10 x - 5 x = 5 x:
5 x + 20 = (5 x - 5 x) + 40
5 x - 5 x = 0:
5 x + 20 = 40
Subtract 20 from both sides:
5 x + (20 - 20) = 40 - 20
20 - 20 = 0:
5 x = 40 - 20
40 - 20 = 20:
5 x = 20
Divide both sides of 5 x = 20 by 5:
(5 x)/5 = 20/5
5/5 = 1:
x = 20/5
The gcd of 20 and 5 is 5, so 20/5 = (5×4)/(5×1) = 5/5×4 = 4:
Answer: x = 4
Answer: 1 and 1/2
Step-by-step explanation:
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Step-by-step explanation:
2
Answer:
x = 3 && y = - 1
Step-by-step explanation:
Just solving the two equations
the first equation
y = 4/3 x +3
y - 4/3 x = 3 ..............................................(1)
the second equation
y = -2/3x -3
y + 2/3 x = -3 ..............................................(2)
by substracting 2 from 1
-4/3x - 2/3x = -6
divide by -1
4/3x +2/3x = 6
6/3x = 6
2x = 6
x= 3
then subsititute by value x in any of given eqautions
Answer:
there are 6 boys in the class
Step-by-step explanation:
