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3 years ago

Solve for y: 1/3y+7 >or equal to 12

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{1}{3} y\geq 12-7\\y\geq 5*3\\or y\geq 15$

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Find the generating function for the sequence 1,-2,4,-8, 16, ...

kirill [66]

Answer:

$a(x)=\dfrac{1}{1+2x}$

Step-by-step explanation:

The generating function a(x) produces a power series ...

$a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots$

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

$a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}$

This can be rearranged to ...

$a_n+2a_{n-1}=0$

We can formulate this in terms of a(x) as follows, then solve for a(x).

$\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}$

The generating function is ...

a(x) = 1/(1+2x)

3 0

3 years ago

Read 2 more answers

How do I evaluate the expression? What steps do I take?

Bingel [31]

Answer:

$\frac{4+8-2}{6-4}*3-1=\frac{12-2}{2}*3-1\\\\=\frac{10}{2}*3-1=5*3-1=15-1=14$

Step-by-step explanation:

8 0

3 years ago

If vector u has its initial point at (-17, 4) and its terminal point at (8,-11), u =

miskamm [114]

Step-by-step explanation:

u vector components:

x-comp = 8 - (-17) = 25

x-comp = -11 - 4 = -15

Therefore, we can write vector u as

u = 25i - 15j

v = 14i - 4j

u - v = 11i - 11j

Therefore,

2(u - v) = 22i - 22j

6 0

3 years ago

Solve the system of equations below.<br> (2x - y = 3<br> (x+2y = -6

lapo4ka [179]

2x - y = 3 = x=0.5y+1.5

x+2y = -6 = x=−2y−6

3 0

3 years ago

Select ALL the correct answers.

horsena [70]

Answer:

1,5,6

Step-by-step explanation:

5 0

3 years ago

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