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3 years ago

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Jack divided his fortune of 92,000 into 8 equal portions.He gave 4 portions to his wife , 1 portion to his son and divided the r

emaining portions equally among 5 charities. How much more money did his son get than each charity?

1 answer:

AleksAgata [21]3 years ago

5 0

Answer:

Step-by-step explanation:

Given that Jack divided his fortune of 92,000 into 8 equal portions.He gave 4 portions to his wife , 1 portion to his son and divided the remaining portions equally among 5 charities.

The portion son gets = $1/8 of 92000 = 11500 $$

Charity on the whole gets = 3 portions = $3/8 *92000 = 34500$$

Each charity gets = $34500/5 = 6900$$

Thus we find son gets 11500 dollars while each charity gets 6900 dollars.

The difference = $11500-6900\\= 4600$

4600 dollars he got more.

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4x + y = 7<br>3x + 2y = 9

Diano4ka-milaya [45]

Answer:

x = 1

y = 3

Step-by-step explanation:

<h2><em><u>Substitution Method</u></em><em><u>:</u></em></h2>

Step 1:

Name The Equation

4x + y = 7 ...(1)

3x + 2y = 9 ...(2)

Step 2:

From Equation (1) we get,

4x = 7 - y

i.e.,

x = 7 - y/4

Step 3:

Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)

i.e.,

3(7 - y/4) + 2y = 9

21 - 3y/4 + 2y = 9

21 - 3y + 8y/4 = 9

21 - 3y + 8y = 9 * 4

21 + 5y = 36

5y = 36 - 21

5y = 15

y = 15/5

<em><u>y = 3</u></em>

Step 4:

Substitute the value of <em><u>y = 3</u></em> in equation (1)

4x + y = 7

i.e.,

4x + (3) = 7

4x + 3 = 7

4x = 7 - 4

4x = 4

x = 4/4

<em><u>x = 1</u></em>

<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>

4x + y = 7 i.e., <em>4(1) + (3) = 7</em>

3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>

3 0

2 years ago

Gavin's dog had a litter of puppies. All of the puppies in this litter were either yellow or black. If there was one less black

mezya [45]

Answer:

Total number of puppies in the litter = 11

Step-by-step explanation:

Let the number of yellow puppies in the litter = y

And the number of black puppies in the litter = b

If there was one less black puppy, ratio of yellow to black puppies = $\frac{2}{3}$

$\frac{y}{b-1}=\frac{2}{3}$

2(b - 1) = 3y

3y - 2b = -2 -----(1)

If there was one more black puppy, ratio of yellow puppies to black puppies = $\frac{1}{2}$

$\frac{y}{b+1}=\frac{1}{2}$

2y = b + 1

2y - b = 1 -------(2)

Equation (1) - 2× equation (2)

(3y - 2b) - 2(2y - b) = -2 - 2

3y - 4y - 2b + 2b = -4

y = 4

From equation (1),

3×4 - 2b = -2

12 - 2b = -2

-2b = -14

b = 7

Total number of puppies in the litter = 7 + 4 = 11

4 0

3 years ago

Please solve with explanation I’ve been asking all day (this is not a multiple choice question)

Anastaziya [24]

Answer:

a) $SA = 522.9~cm^2$

b) $V_{cone} = 670.2~cm^3$

c) $V_{empty} = 1340.4~cm^3$

Step-by-step explanation:

a)

For a cone,

$SA = \pi r (L + r)$

where L = slant height

$L = \sqrt{r^2 + h^2}$

We have r = 8 cm; h = 10 cm

$L = \sqrt{(8~cm)^2 + (10~cm)^2}$

$L = \sqrt{164~cm^2}$

$SA = (\pi)(8~cm)(\sqrt{164~cm^2} + 8~cm)$

$SA = 522.9~cm^2$

b)

$V_{cone} = \dfrac{1}{3}\pi r^2 h$

$V_{cone} = \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)$

$V_{cone} = 670.2~cm^3$

c)

$V_{cylinder} = \pi r^2 h$

empty space = volume of cylinder - volume of cone

$V_{empty} = V_{cylinder} - V_{cone}$

$V_{empty} = \pi r^2 h - \dfrac{1}{3}\pi r^2 h$

$V_{empty} = (\pi)(8~cm)^2(10~cm) - \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)$

$V_{empty} = 1340.4~cm^3$

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3 years ago

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mrs_skeptik [129]

Answer:

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Step-by-step explanation:

5832÷9=648

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Answer:

B.

Step-by-step explanation:

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