Answer:
(D)Rational
Step-by-step explanation:
Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides,
and
. A 95% large-sample CI for the true average percentage elongation is given by
, i.e.,
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
5x+2/5=x-1/10
Convert 2/5 and -1/10 to equal fractions.
2/5= 4/10
5x+4/10= x-1/10
Subtract x on both sides.
4x+4/10= 1/10
Subtract 4/10 on both sides.
4x=-3/10
Divide both sides by 4.
x=-0.075
I hope this helps!
~kaikers