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2 years ago

Please help me with this question

Mathematics

1 answer:

Umnica [9.8K]2 years ago

6 0

Answer:

it's A

Step-by-step explanation:

I Think so

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Solve each equation by completing the square <br> 6) m² + 16m – 8 = 0

Natali5045456 [20]

Answer:

m = - 8 ± 6 $\sqrt{2}$

Step-by-step explanation:

Given

m² + 16m - 8 = 0 ( add 8 to both sides )

m² + 16m = 8

To complete the square

add ( half the coefficient of the m- term )² to both sides

m² + 2(8)m + 64 = 8 + 64

(m + 8)² = 72 ( take the square root of both sides )

m + 8 = ± $\sqrt{72}$ = ± $\sqrt{36(2)}$ = ± 6 $\sqrt{2}$

Subtract 8 from both sides

m = - 8 ± 6 $\sqrt{2}$

3 0

3 years ago

Will mark brainliest lol

BabaBlast [244]

Answer:

x=17

The angles are Vertical.

Step-by-step explanation:

6x17 equals 102. Then subtract 12 from 102 to get 90 degrees.

6(17)-12=90 degrees

3 0

3 years ago

Read 2 more answers

80 points!!

GaryK [48]

6/9 is equal to 2/3 is equal to 4/6. Equivalent fraction visually. Equivalent fractions on the number line. Equivalent fractions on the number line.

8 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

8.) Write y = 3/5 x + 4 in standard form using integers.

Tju [1.3M]

Answer:

I believe the answer is c

Step-by-step explanation:

What i got tho was... 3x-5y=-20

7 0

3 years ago