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Harlamova29_29 [7]
3 years ago
9

HELP ME LLEASE WUIZ OMG WHAT ARE THE CORDS? 30 points

Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer: -1/2 and 1/3

Step-by-step explanation:

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Malcolm is filling bags with rice. He starts with a 5 1/4 pound container of rice and fills each
Sliva [168]

Basically we want to know how many times 5/8 goes into 5 1/4.

5 1/4 ÷ 5/8 = 21/4 ÷ 5/8 = 21/4 × 8/5 = 42/5 = 8.4 bags

Since we cannot have a fraction of a bag, he can fill 8 bags completely.

answer: 8 bags

6 0
3 years ago
Can someone please help me with this question? Please and thanks in advance
matrenka [14]
These two lines create vertical angles, which are congruent. That means angle z = 60 degrees. Since angle z and the angle represented by the expression 6x + 60 are supplementary (they are adjacent angles that add to equal 180 degrees), you can set up the following equation to find x:

6x + 60 + 60 = 180
6x + 120 = 180
6x = 60
x = 10

Answers:
x = 10
z = 60
3 0
3 years ago
HELPP!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step.  The equation is

8-3\sqrt[5]{x^3}=-7

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time.  First thing is to subtract 8 from both sides:

-3\sqrt[5]{x^3}=-15

The goal is to isolate the term with the x in it, so that means that the -3 has to go.  Divide it away on both sides:

\sqrt[5]{x^3}=5

Let's rewrite that radical into exponential form:

x^{\frac{3}{5}}=5

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely.  On the right, let's rewrite that back in radical form to solve it easier:

x=\sqrt[3]{5^5}

Let's group that radicad into groups of 3's now to make the simplifying easier:

x=\sqrt[3]{5^3*5^2} because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

x=5\sqrt[3]{5^2} which is the same as:

x=5\sqrt[3]{25}

8 0
3 years ago
Which ordered pairs in the form (x, y) are solutions to the equation
Levart [38]
The answer is a and c
4 0
2 years ago
The sum of twice a number and five is 13. Find the number.
Eduardwww [97]

4

let the number be x

so by the question , 2x+5=13

solving this we get ,

2x=13-5

2x=8

so x=4

6 0
3 years ago
Read 2 more answers
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