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finlep [7]
2 years ago
10

Line t has slope 3/4 and passes through (0, 0) . Follow these steps:Step

Mathematics
1 answer:
mina [271]2 years ago
7 0

Answer:

(8,0)

Step-by-step explanation:

y=mx+b

0=(3/4)0+b

0=b

y=3/4x+0

the point eight units away from (0,0)

is (8,0)

Hope this helps :)

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Please help me! DO NOT SEND LINK!
svet-max [94.6K]

Answer:

<u>So option 4; </u>\frac{35}{100}<u> is the correct option</u>

Step-by-step explanation:

First, we need to convert \frac{2}{10} so it's denominator is 100. To do so, we will multiply the numerator and denominator by 10

\frac{2}{10} *\frac{10}{10} = \frac{20}{100}

Second, we need to add the two fractions to get the current total distance walked. Remember, when adding fractions, the denominator does not change.

\frac{45}{100} + \frac{20}{100} = \frac{65}{100}

Now that we have the total distance walked, we need to subtract that to 1 mile. 1mile=\frac{1}{1} = \frac{10}{10} =\frac{100}{100}

\frac{100}{100} -\frac{65}{100} = \frac{35}{100}

So option 4; \frac{35}{100} is the correct option

6 0
3 years ago
3
Pani-rosa [81]

Answer:

i thinks it's b

Step-by-step explanation:

I do not no tho

3 0
3 years ago
What is 16500 rounded to the nearest ten thousand?
frosja888 [35]
16500 Rounded to the nearest ten thousand is 20,000
4 0
3 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
2 years ago
F(x) = 3x + 2 What is f(5)?
Ulleksa [173]

Answer:

if the equation if f(x) = 3x + 2, then f(5) would be equal to 3*5 + 2 = 17.

Step-by-step explanation:

8 0
3 years ago
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