Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
2y = 2x + 10
y = x + 5
m = 1
