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2 years ago

Which unit of measurement is the best unit to be used in measuring the weight of an adult?

Mathematics

1 answer:

telo118 [61]2 years ago

8 0

Pounds. this is the unit that i commonly see around when people discuss their weights

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Cuanto es (4x+5)(4x+5)

Pachacha [2.7K]

Answer:

16x^2+40x+25

Step-by-step explanation:

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3 years ago

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PLEASE HELP WORTH 99 POINTS AND CORRECT ANSWER WILL GET BRAINLIEST

Soloha48 [4]

Hello!

I believe the answers are:

A) The vertex is (1, −6)

C) The graph has a minimum.

I hope it helps!

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3 years ago

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You are making a poster to support your friend for homecoming. Your original photo is 4 inches by 6 inches. You want the photo o

Lorico [155]

Answer:

Step-by-step explanation:

We have been given that dimensions of original photo are 4 inches by 6 inches. We want the photo on the poster to be of dimensions 3 feet by 4 1/2 feet.

First of all we will convert dimensions of poster from feet to inches.

$3\text{ feet}=3\times 12 \text{ inches}=36\text{ inches}$

$4\frac{1}{2}\text{ feet}=4.5\times 12 \text{ inches}=54\text{ inches}$

Now let us compare sides of our original photo with corresponding sides of poster.

$\frac{36}{4} =9$

Now let us compare the second pair of corresponding sides.

$\frac{54}{6} =9$

We have seen that sides of poster are 9 times the sides of our original photo, therefore, the scale factor of this dilation is 9.

5 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

Solve Ax+Hy=K for x<br> Help!

denis23 [38]

Answer:

$x = -\frac{Hy + K}{A}$

Step-by-step explanation:

Step 1: Add -Hy to both sides.

$Ax + Hy - Hy = K - Hy$
$Ax = -Hy + K$

Step 2: Divide both sides by A.

$\frac{Ax}{A} = \frac{-Hy+K}{A}$
$x = -\frac{Hy+K}{A}$

3 0

3 years ago