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Sergio [31]
3 years ago
15

a total of 1500 raffle tickets were collected during the school fair. if you have 30 raffle tickets, what is the probability tha

t you will win?​
Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer: 1/50 or 0.02

Step-by-step explanation:

30 / 1500 = 1/50

1/50 or 0.02

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Graph: y=-4sin(2x)+1 where the x axis starts at 30​
gregori [183]

Answer:

We want to graph:

y = -4*sin(2*x) + 1

Such that the x-axis starts at x = 30

This is trivial to do if we use a program to graph or if we graph by hand, here we just need to draw the x-axis such that it crosses the y-axis at the point (30, 0)

Then let's graph the equation in that axis, we will get an image like the one you can see below.

8 0
3 years ago
What is the slope of the line ?
nikitadnepr [17]

Answer:

-3/4

Step-by-step explanation:

To find the slope of a line, you need to see how much it "rises" over a certain amount of "run". In other words, for a given amount of distance traveled along the x axis, how much it traveled vertically along the y axis. In this line, for every 4 units moved to the right, the line goes up by -3 units. Therefore, the slope of the line is -3/4. Hope this helps!

4 0
3 years ago
Read 2 more answers
Initially, a population of rabbits was found to contain 192 rabbits. It was estimated that the population was growing exponentia
aleksley [76]

Answer:

the population after 52 days is $34,804.27

Step-by-step explanation:

Given that

There is a population of the rabbits i.e. 192

And, the growth rate is 10%

We need to find out the population after 52 days

So,

= 192 × e^(0.10 × 52)

= $34,804.27

hence, the population after 52 days is $34,804.27

7 0
3 years ago
What is the constant term in the expression 6x3y + 8x2 + 5x + 7? (Input a numeric value only.)
dem82 [27]
The constant term in the expression is 7
4 0
3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
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