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attashe74 [19]
3 years ago
14

Tim wrote the following statement:

Mathematics
2 answers:
hodyreva [135]3 years ago
5 0

Answer:

My answer would be: Tim is incorrect, because more than one triangle can be drawn with the given information.

Given:

Isosceles triangle and has a 70° angle.

An isosceles triangle is a triangle that has 2 congruent angle. Since all interior angle must have a sum of 180°, the possible angles of an isosceles triangle with a 70° angle are:

1) 180° - 70° = 110°

110° / 2 = 55°

Angles are 70°-55°-55°

2) 180° - 70° = 110°

110° - 70° = 40°

Angles are 70°-70°-40°

The given information can create 2 isosceles triangle. Thus, Tim is wrong in his claims.

You're welcome!

sukhopar [10]3 years ago
4 0

Answer:

Step-by-step explanation:

I think its A IF NOT ITS B

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First you have to change them all to the same form, so you have to pick one out of them, so for instance you could pick percent which would be; 23%, 19%, and 20%, so from least to greatest it would be; 19%, 20%, and 23%. Hope this helps! 
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3 years ago
Convert from rectangular to polar coordinates:Note: Choose r and θ such that r is non-negative and 0 ≤ θ < 2πa. (6,0)b. (9,9/
Anuta_ua [19.1K]

Answer:

The polar coordinates are as follow:

a. (6,2π)

b. (18, π/3)

c. (2√2 , 3π/4)

d. (2, 5π /6)

Step-by-step explanation:

To convert the rectangular coordinates into polar coordinates, we need to calculate r, θ .

To calculate r, we use Pythagorean theorem:

r = \sqrt{ x^{2} +y^{2} } ---- (1)

To calculate the θ, first we will find out the θ '  using the inverse of cosine as it is easy to calculate.

So,    θ '  = cos ⁻¹  (x/r)

If  y  ≥  0  then  θ  =  ∅

If  y  <  0  then  θ  =  2 π  −  ∅

For a. (6,0)

Sol:

Using the formula in equation (1). we get the value of r as:

r = \sqrt{6^{2} + 0^{2}  }

r = 6

And ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (6/6)

∅  =cos ⁻¹   (1) = 2π

As If  y  ≥  0  then  θ  =  ∅

So ∅ = 2π

The polar coordinates are (6,2π)

For a. (9,9/\sqrt{3})

Sol:

r = 9 + 3(3) = 18

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (9/18)

∅ = cos ⁻¹   (1/2) = π/3

As  If  y  ≥  0  then  θ  =  ∅

then θ  = π/3

The polar coordinates are (18, π/3)

For (-2,2)

Sol:

r =√( (-2)²+(2)² )

r = 2 √2

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (-2/ 2 √2)

∅ = 3π/4

As  If  y  ≥  0  then  θ  =  ∅

then   θ  = 3π/4

The polar coordinates are (2√2 , 3π/4)

For (-√3, 1)

Sol:

r = √ ((-√3)² + 1²)

r = 2

and ∅  = cos ⁻¹  (x/r)

∅  = cos ⁻¹ ( -√3/2)

∅  = 5π /6

As  If  y  ≥  0  then  θ  =  ∅

So  θ  = 5π /6

The polar coordinates are (2, 5π /6)

6 0
2 years ago
Please help asap! really important!!
Alexxandr [17]

Answer:

4th graph

6th graph

3rd graph

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it is 4th graph

when you substitute x = 0 y is 3

and when y = 0 x is -3

Quadratic = y = 3x^2

It is 6th graph

for both positive and negative values of x, y is rapidly increasing

Exponential = y = 3^x

it is 3rd graph

for x = 0 y value is 1 because 3^0 = 1

for positive values of x, y is exponentially rising

for negative values of x it is nearly almost touches zero

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